Chapter 35 — Interference

14 points · 3 extra credit

Chapter 35 — Interference

Core: 14 points · Extra credit: 3 points. Show your reasoning; partial credit is given.

Worked solutions are available for every problem.
  1. 1. (1 pt •) Two loudspeakers driven by the same amplifier emit identical waves of wavelength λ=480 nm\lambda=480\,\text{nm} (treat as coherent light sources for this problem). At a certain point the waves from the two sources have traveled path lengths that differ by Δr=1.44 μm\Delta r = 1.44\,\mu\text{m}.

    Is the interference at that point constructive or destructive? Justify with the ratio Δr/λ\Delta r/\lambda.

    #
  2. 2. (2 pts ••) In a Young's double-slit experiment the slits are separated by d=0.20 mmd=0.20\,\text{mm} and the screen is L=1.8 mL=1.8\,\text{m} away. Monochromatic light of wavelength λ=550 nm\lambda=550\,\text{nm} is used.

    (a) Find the spacing between adjacent bright fringes on the screen.

    (b) How far from the central maximum is the tenth-order (m=10m=10) bright fringe?

    #
  3. 3. (2 pts ••) Coherent light of wavelength λ=633 nm\lambda=633\,\text{nm} passes through two slits separated by d=0.12 mmd=0.12\,\text{mm}.

    (a) At what angle θ\theta (measured from the central axis) does the second-order bright fringe appear?

    (b) If the slit separation were instead d=2.5 μmd=2.5\,\mu\text{m}, how many bright fringes in total would appear on a distant screen? (Count all orders that satisfy ∣sin⁡θ∣≤1|\sin\theta|\le 1.)

    #
  4. 4. (2 pts ••) Two identical coherent sources illuminate a screen; at the center of the pattern (zero path difference) the combined intensity is I0I_0. At a point PP their waves arrive with a path difference Δr\Delta r, giving a combined intensity I=I0cos⁡2(ϕ/2)I=I_0\cos^2(\phi/2), where ϕ\phi is the phase difference.

    (a) Find the phase difference ϕ\phi (in radians and degrees) when Δr=0.10 λ\Delta r = 0.10\,\lambda, and evaluate I/I0I/I_0 there.

    (b) For what smallest nonzero path difference (as a fraction of λ\lambda) does the intensity fall to one-quarter of its central-maximum value?

    #
  5. 5. (2 pts ••) A soap film (n=1.33n=1.33) of uniform thickness t=320 nmt=320\,\text{nm} is surrounded by air and illuminated at normal incidence with white light.

    (a) Explain why light reflected from the front surface undergoes a half-cycle (π\pi) phase shift while light reflected from the back surface does not.

    (b) Which visible wavelength (400400–700 nm700\,\text{nm}) is most strongly reflected? Identify its color.

    #
  6. 6. (2 pts ••) A lens is to be coated with a single layer of magnesium fluoride (n=1.38n=1.38) to minimize reflection of λ=550 nm\lambda=550\,\text{nm} light at normal incidence. The lens glass has n=1.52n=1.52.

    (a) Both reflections (air→coating and coating→glass) occur at a surface of higher index, so each reflected ray gets a π\pi phase shift. Explain whether these two shifts add or cancel, and use that to write the correct condition on 2nt2nt for destructive interference (a dark, non-reflecting result) of the reflected light.

    (b) Find the minimum (nonzero) coating thickness.

    #
  7. 7. (3 pts •••) In a Newton's-rings apparatus a plano-convex lens of radius of curvature R=10.0 mR=10.0\,\text{m} rests on a flat glass plate, and the gap is illuminated from above with sodium light, λ=589 nm\lambda=589\,\text{nm}. Viewed in reflection, a pattern of concentric dark rings appears.

    (a) By considering the two reflected rays from the top and bottom of the air gap, show that the dark rings occur where the gap thickness satisfies 2t=mλ2t=m\lambda (m=0,1,2,…m=0,1,2,\dots), and hence that the radius of the mm-th dark ring is rm=mλRr_m=\sqrt{m\lambda R}. (Use t≈r2/2Rt \approx r^2/2R for the thin gap.)

    (b) Compute the radius of the fifth dark ring (m=5m=5).

    #
  8. Extra Credit (3 pts •••)

    Two slits act as identical coherent sources. Each alone produces at a point PP on a distant screen a field of amplitude E0E_0, i.e. E1(t)=E0cos⁡ωtE_1(t)=E_0\cos\omega t and E2(t)=E0cos⁡(ωt+ϕ)E_2(t)=E_0\cos(\omega t+\phi), where ϕ\phi is the phase difference from the path-length difference between the two slits and PP.

    (a) By adding the two waves — either with the trigonometric sum-to-product identity or by adding phasors (vectors of length E0E_0 separated by angle ϕ\phi) — show that the resultant field is a single cosine of amplitude

    EP=2E0cos⁡ ⁣(ϕ2).E_P = 2E_0\cos\!\left(\frac{\phi}{2}\right).

    (b) Intensity is proportional to the square of the field amplitude. Using the fact that a single source alone gives I0∝E02I_0 \propto E_0^2, derive

    I=I0cos⁡2 ⁣(ϕ2),I = I_0\cos^2\!\left(\frac{\phi}{2}\right),

    and identify the value of II at the maxima in terms of I0I_0. Explain in one sentence why this is not a violation of energy conservation.

    (c) Relate ϕ\phi to the path difference Δr\Delta r and, for small angles in a double-slit geometry (Δr=dsin⁡θ≈d y/L\Delta r = d\sin\theta \approx d\,y/L), show that this intensity formula reproduces bright fringes at ym=mλL/dy_m=m\lambda L/d.

    #