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The Timpson Lyceum · University Physics II (2026) – Electricity & Magnetism

Chapter 31 — Alternating Current

Problem sheet · 13 points · 3 extra credit

Chapter 31 — Alternating Current

Core: 13 points · Extra credit: 3 points. Show your reasoning; partial credit is given.

  1. 1. (1 pt •) A household outlet supplies a sinusoidal voltage with amplitude V0=170 VV_0=170\,\text{V} at f=60 Hzf=60\,\text{Hz}.

    (a) Find the rms voltage.

    (b) A resistive heater draws a current of amplitude I0=2.5 AI_0=2.5\,\text{A}. Find the rms current.

  2. 2. (2 pts ••) A 0.25 H0.25\,\text{H} inductor and, separately, an 8.0 μF8.0\,\mu\text{F} capacitor are each driven at f=60 Hzf=60\,\text{Hz}.

    (a) Find the inductive reactance XLX_L and the capacitive reactance XCX_C.

    (b) If each element alone is connected across a 120 V120\,\text{V} (rms) source at this frequency, find the rms current through each.

    (c) Without recomputing, state how each reactance changes if the frequency is doubled.

  3. 3. (2 pts ••) In a series circuit driven at a single frequency, the voltage amplitudes measured across the resistor, inductor, and capacitor are VR=45 VV_R=45\,\text{V}, VL=80 VV_L=80\,\text{V}, and VC=40 VV_C=40\,\text{V}.

    (a) Using a phasor diagram, find the amplitude of the source voltage.

    (b) Find the phase angle of the source voltage relative to the current, and state whether the current leads or lags the source.

  4. 4. (3 pts •••) A series R–L–C circuit has R=200 ΩR=200\,\Omega, L=0.40 HL=0.40\,\text{H}, and C=5.0 μFC=5.0\,\mu\text{F}, driven by a source of rms voltage 120 V120\,\text{V} at f=60 Hzf=60\,\text{Hz}.

    (a) Find XLX_L, XCX_C, and the impedance ZZ.

    (b) Find the rms current.

    (c) Find the phase angle ϕ\phi, and state whether the circuit is inductive or capacitive.

    (d) Find the average power delivered by the source, and check it against Irms2RI_\text{rms}^2 R.

  5. 5. (2 pts ••) For the same components as Problem 4 (L=0.40 HL=0.40\,\text{H}, C=5.0 μFC=5.0\,\mu\text{F}, R=200 ΩR=200\,\Omega, source rms voltage 120 V120\,\text{V}):

    (a) Find the resonance angular frequency ω0\omega_0 and the corresponding frequency f0f_0.

    (b) Find the rms current and the average power delivered at resonance, and explain why the power is larger than in Problem 4.

  6. 6. (2 pts ••) An AC motor operating from a 240 V240\,\text{V} (rms) line draws an rms current of 5.0 A5.0\,\text{A} with a power factor of 0.800.80 (current lagging).

    (a) Find the average power consumed by the motor.

    (b) Find the phase angle between the line voltage and the current.

    (c) The apparent power is VrmsIrmsV_\text{rms}I_\text{rms}. Find it, and explain in one sentence why it exceeds the average power.

  7. 7. (1 pt •) An ideal transformer has a primary of 800800 turns and a secondary of 100100 turns, with 120 V120\,\text{V} (rms) applied to the primary.

    (a) Find the secondary voltage.

    (b) The secondary drives a 3.0 Ω3.0\,\Omega resistive load. Find the secondary current and the primary current.

  8. Extra Credit (3 pts •••)

    A series R–L–C circuit is driven by a source v(t)=V0cos⁡ωtv(t)=V_0\cos\omega t, and carries current i(t)=I0cos⁡(ωt−ϕ)i(t)=I_0\cos(\omega t-\phi), where ϕ\phi is the phase by which the current lags the voltage.

    (a) Starting from the instantaneous power p(t)=v(t) i(t)p(t)=v(t)\,i(t), integrate over one full period T=2π/ωT=2\pi/\omega to derive the average power

    Pav=12V0I0cos⁡ϕ=VrmsIrmscos⁡ϕ.P_\text{av}=\tfrac{1}{2}V_0 I_0\cos\phi = V_\text{rms}I_\text{rms}\cos\phi.

    (b) Write Z(ω)=R2+(ωL−1ωC)2Z(\omega)=\sqrt{R^2+\left(\omega L-\dfrac{1}{\omega C}\right)^2}. By setting dZ/dω=0dZ/d\omega=0, prove that the impedance is a minimum (and therefore the current amplitude a maximum) exactly at ω0=1/LC\omega_0=1/\sqrt{LC}.

    (c) Using part (a), show that the average power dissipated is maximized at ω0\omega_0, and give its value there in terms of V0V_0 and RR.