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The Timpson Lyceum · University Physics II (2026) – Electricity & Magnetism

Introduction to University Physics II – Lecture 0 (University Physics II)

Introduction to University Physics II – Lecture 0

Overview

This opening lecture sets up the whole course (Electricity & Magnetism, i.e. University Physics II) by building the mathematical and physical toolkit you will need before any circuits or fields appear. It compresses an entire first calculus course — limits, continuity, derivatives, and integrals — into a single intuition-first pass. It then grounds those ideas in physics through Galileo's falling-body experiment, showing how position, velocity, and acceleration are linked by derivatives and integrals. Finally it introduces the principle of relativity and the distinction between scalars and vectors. The goal is double exposure: meet everything once now, so it feels familiar when it returns at a slower pace.

Key Concepts

Electricity & magnetism as a fundamental force. Of the four fundamental forces (gravity, electromagnetism, weak nuclear, strong nuclear), nearly every everyday phenomenon that is not gravity is electromagnetic: sound (electrons in vibrating matter repelling air molecules), sight (photons emitted and absorbed by electrons changing energy level), and all of chemistry.

Limit. The value a function's output approaches as the input gets arbitrarily close to a point — not the value at the point itself. For most points the limit equals the function's value, but they can differ where the function has a hole. lim⁡x→af(x)=L\lim_{x \to a} f(x) = L

Continuity. A function is continuous if you can draw it without lifting your pencil. Precisely, ff is continuous at aa when the value equals the limit: f(a)=lim⁡x→af(x)f(a) = \lim_{x \to a} f(x)

Slope of a line. Rise over run, the same everywhere on a line: m=ΔyΔx=y2−y1x2−x1m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} This yields the point–slope form y−y1=m(x−x1)y - y_1 = m(x - x_1) and the slope–intercept form y=mx+by = mx + b, where bb is the yy-intercept.

Derivative. The slope of a function at a point. Since slope needs two points, take a second point a distance Δx\Delta x away, form the secant slope, and let Δx→0\Delta x \to 0: f′(x)=lim⁡Δx→0f(x+Δx)−f(x)Δxf'(x) = \lim_{\Delta x \to 0} \frac{f(x + \Delta x) - f(x)}{\Delta x} Notations f′(x)f'(x) and dydx\dfrac{dy}{dx} mean the same thing; the dy/dxdy/dx form ("change in yy with respect to xx") is preferred here because deltas turn into derivatives when you take the limit.

Power rule. A fast shortcut for derivatives — bring the exponent down and subtract one: ddx xn=n xn−1\frac{d}{dx}\,x^n = n\,x^{n-1} The derivative of a constant is 00 (a constant has zero slope).

Integral. The area under a curve from aa to bb. Approximate it with nn rectangles of base Δx\Delta x and height f(x)f(x), then let n→∞n \to \infty: ∫abf(x) dx=lim⁡n→∞∑k=1nf ⁣(a+kb−an)b−an\int_a^b f(x)\,dx = \lim_{n \to \infty} \sum_{k=1}^{n} f\!\left(a + k\tfrac{b-a}{n}\right)\frac{b-a}{n} Shortcut (reverse of the power rule) — add one to the exponent and divide: ∫xn dx=xn+1n+1+C\int x^n\,dx = \frac{x^{n+1}}{n+1} + C

Fundamental Theorem of Calculus. Differentiation and integration undo each other; the integral of a derivative recovers the original function.

Kinematics. Position x(t)x(t), velocity, and acceleration form a derivative chain:

Galileo's falling body. Ignoring air resistance, objects accelerate downward at a constant g≈9.8 m/s2g \approx 9.8\ \text{m/s}^2 (often rounded to 10 m/s210\ \text{m/s}^2 for easy arithmetic), independent of mass. With a=10a = 10, integrating once gives v(t)=10tv(t) = 10t and again gives x(t)=5t2x(t) = 5t^2.

Relativity (Galilean). Position and velocity are relative — they can only be stated with respect to some other object or event; there is no absolute position or absolute velocity. Acceleration, however, is not relative: you can always feel and agree on who is accelerating.

Scalars vs. vectors. A scalar is a single magnitude (distance, speed). A vector needs magnitude and direction, requiring more than one number (position, displacement, velocity), and is drawn as an arrow. Displacement (end minus start position) can be negative and tracks direction; distance (total path length) cannot.

Worked Example

Find the slope (derivative) of f(x)=x2−1f(x) = x^2 - 1 at a general point xx using the limit definition, then confirm with the power rule.

f′(x)=lim⁡Δx→0f(x+Δx)−f(x)Δx=lim⁡Δx→0[(x+Δx)2−1]−[x2−1]Δx=lim⁡Δx→0x2+2x Δx+Δx2−1−x2+1Δx=lim⁡Δx→02x Δx+Δx2Δx=lim⁡Δx→0 (2x+Δx)=2x\begin{aligned} f'(x) &= \lim_{\Delta x \to 0} \frac{f(x + \Delta x) - f(x)}{\Delta x} \\ &= \lim_{\Delta x \to 0} \frac{\big[(x+\Delta x)^2 - 1\big] - \big[x^2 - 1\big]}{\Delta x} \\ &= \lim_{\Delta x \to 0} \frac{x^2 + 2x\,\Delta x + \Delta x^2 - 1 - x^2 + 1}{\Delta x} \\ &= \lim_{\Delta x \to 0} \frac{2x\,\Delta x + \Delta x^2}{\Delta x} \\ &= \lim_{\Delta x \to 0} \,(2x + \Delta x) \\ &= 2x \end{aligned}

The power rule gives the same result instantly: ddx(x2−1)=2x\dfrac{d}{dx}(x^2 - 1) = 2x. So the slope at x=1x = 1 is 22 and at x=2x = 2 is 44, matching the graph.

Summary