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The Timpson Lyceum · Real Analysis (2020)

Lecture 1 (Real Analysis 2020)

Overview

This opening lecture lays the logical and set-theoretic groundwork the whole course rests on, then takes the first real step into analysis: the field axioms for the real numbers. The aim is not to "do calculus" but to learn to reason deductively — to take a set of premises and derive their logical consequences. We review the three modes of reasoning (deductive, inductive, abductive) and commit to deductive reasoning alone, then build up propositional logic, sets, relations, and functions. Finally, we treat R\mathbb{R} as an undefined set equipped with two undefined operations ++ and ⋅\cdot obeying the field axioms, and prove several familiar arithmetic facts strictly from those axioms.

Key Concepts

Three kinds of reasoning

Propositional logic

Sets

Lists, relations, functions

The field axioms for R\mathbb{R} We treat R\mathbb{R}, ++, and ⋅\cdot as undefined, assuming only that +,⋅+,\cdot are closed on R\mathbb{R} and satisfy:

  1. Commutativity — x+y=y+xx+y=y+x,  x⋅y=y⋅x\ x\cdot y=y\cdot x.
  2. Associativity — (x+y)+z=x+(y+z)(x+y)+z=x+(y+z), similarly for ⋅\cdot.
  3. Additive identity — ∃ 0\exists\,0 with 0+x=x0+x=x for all xx.
  4. Multiplicative identity — ∃ 1\exists\,1 with 1⋅x=x1\cdot x=x for all xx.
  5. Additive inverse — ∀x, ∃y\forall x,\ \exists y with x+y=0x+y=0.
  6. Multiplicative inverse — ∀x≠0, ∃y\forall x\neq 0,\ \exists y with x⋅y=1x\cdot y=1.
  7. Distributivity — x⋅(y+z)=x⋅y+x⋅zx\cdot(y+z)=x\cdot y + x\cdot z.
  8. Nontriviality — 0≠10\neq 1 (rules out the one-element set).

From these one proves uniqueness of 00 and of inverses, allowing the definitions −x-x (the unique additive inverse), x−1x^{-1} (the unique multiplicative inverse, x≠0x\neq0), and x−y:=x+(−y)x-y := x+(-y). Substituting equal quantities into an operation ("add the same thing to both sides") is a rule of logic, not an axiom.

Worked Example

Claim. From the field axioms, 0⋅x=00\cdot x = 0 for every x∈Rx\in\mathbb{R}.

The key levers are the additive-identity axiom 0+0=00+0=0, distributivity, and the left cancellation law (a+b=a+c⇒b=ca+b=a+c \Rightarrow b=c, itself proved by adding −a-a to both sides).

0=0+0(additive identity)x⋅0=x⋅(0+0)(apply x⋅ to both sides)x⋅0=x⋅0+x⋅0(distributivity)x⋅0+0=x⋅0+x⋅0(additive identity, LHS)0=x⋅0(left cancellation of x⋅0)0=0⋅x(commutativity).\begin{aligned} 0 &= 0 + 0 &&\text{(additive identity)}\\ x\cdot 0 &= x\cdot(0+0) &&\text{(apply $x\cdot$ to both sides)}\\ x\cdot 0 &= x\cdot 0 + x\cdot 0 &&\text{(distributivity)}\\ x\cdot 0 + 0 &= x\cdot 0 + x\cdot 0 &&\text{(additive identity, LHS)}\\ 0 &= x\cdot 0 &&\text{(left cancellation of $x\cdot 0$)}\\ 0 &= 0\cdot x &&\text{(commutativity)}. \end{aligned}

So no special "multiply-by-zero" axiom is needed — the fact 0⋅x=00\cdot x=0 is forced by the field axioms alone.

Summary