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The Timpson Lyceum · General Topology (Point Set Topology)

Closed Sets – Lecture 9 (Topology)

Closed Sets – Lecture 9

Overview

This lecture introduces closed sets, the natural companion to open sets, and defines them entirely in terms of set complements. A set is closed exactly when its complement is open — so "closed" is not the logical opposite of "open"; a set can be open, closed, both, or neither. After building intuition through examples in the standard topology on R\mathbb{R} and R2\mathbb{R}^2, we prove that closed balls are genuinely closed, review De Morgan's laws (with the logic behind them), and use those laws to show that closed sets satisfy three properties mirroring the axioms for open sets. The lecture closes with the Hausdorff separation property — the first true topological property used to classify spaces.

Key Concepts

Open set (review). A set is open precisely when it is a member of the topology τ\tau. The three topology axioms: ∅\varnothing and the whole space XX are open; any finite intersection of open sets is open; any arbitrary union of open sets is open.

Complement. For U⊆XU \subseteq X, the complement is Uc=X∖UU^{c} = X \setminus U — all points of XX not in UU. We write the complement with a superscript cc (reserving the overbar notation for closure, introduced later).

Closed set. Let (X,τ)(X,\tau) be a topological space and A⊆XA \subseteq X. Then A is closed  ⟺  Ac is open.A \text{ is closed} \iff A^{c} \text{ is open}. That is the entire definition — to test whether AA is closed, write down AcA^{c} and ask whether it is open.

Open vs. closed are not opposites. A set may be:

Examples in the standard topology on R\mathbb{R} (open sets = unions of open intervals):

Open and closed balls. In a metric setting, the open ball of radius rr about xx is B(x,r)={ y:d(x,y)<r },B(x,r) = \{\, y : d(x,y) < r \,\}, and the closed ball is B‾(x,r)={ y:d(x,y)≤r }.\overline{B}(x,r) = \{\, y : d(x,y) \le r \,\}. The only difference is whether the boundary (d(x,y)=rd(x,y)=r) is included. Open balls are open sets; closed balls are closed sets. In the standard topology on R2\mathbb{R}^2, open sets are unions of open balls (open disks); in R3\mathbb{R}^3 they are unions of open 3-balls, and so on.

De Morgan's laws (logic). Distributing a negation over a connective flips it: ¬(α∧β)≡(¬α)∨(¬β),¬(α∨β)≡(¬α)∧(¬β).\lnot(\alpha \land \beta) \equiv (\lnot\alpha)\lor(\lnot\beta), \qquad \lnot(\alpha \lor \beta) \equiv (\lnot\alpha)\land(\lnot\beta).

De Morgan's laws (sets). Because x∈A∩Bx\in A\cap B means x∈A∧x∈Bx\in A \land x\in B, the same flip carries over to complements, for any number of sets: (⋂iAi)c=⋃iAic,(⋃iAi)c=⋂iAic.\left(\bigcap_{i} A_i\right)^{c} = \bigcup_{i} A_i^{c}, \qquad \left(\bigcup_{i} A_i\right)^{c} = \bigcap_{i} A_i^{c}. Bringing the complement inside turns intersections into unions and unions into intersections.

Three properties of closed sets. For any topological space (X,τ)(X,\tau):

These are exactly the open-set axioms with intersection and union swapped — and they follow immediately by taking complements and applying De Morgan's laws.

Hausdorff property. A space (X,τ)(X,\tau) is Hausdorff if for any two distinct points x≠yx \ne y there exist disjoint open sets (neighborhoods) U∋xU \ni x and V∋yV \ni y with U∩V=∅U \cap V = \varnothing — you can "house off" any two distinct points into separate neighborhoods. Key facts:

Worked Example

Claim. In the standard topology on R2\mathbb{R}^2, every closed ball B‾(x,r)\overline{B}(x,r) is a closed set.

Strategy. Let U=B‾(x,r)cU = \overline{B}(x,r)^{c}. To show B‾(x,r)\overline{B}(x,r) is closed we show UU is open, i.e. that around every point y∈Uy\in U we can fit an open ball B(y,ε)B(y,\varepsilon) lying entirely in UU; then UU is the union of all such balls, hence open (the "union lemma").

Pick any y∈Uy \in U. Since y∉B‾(x,r)y \notin \overline{B}(x,r), we have d(x,y)>rd(x,y) > r, so d(x,y)−r>0d(x,y) - r > 0. Choose any radius with 0<ε<d(x,y)−r.0 < \varepsilon < d(x,y) - r. It remains to show B(y,ε)∩B‾(x,r)=∅B(y,\varepsilon) \cap \overline{B}(x,r) = \varnothing. Suppose, for contradiction, some point zz lies in both balls. By the triangle inequality, substituting the two ball conditions d(x,z)≤rd(x,z)\le r and d(z,y)<εd(z,y)<\varepsilon, and then ε<d(x,y)−r\varepsilon < d(x,y)-r:

d(x,y)≤d(x,z)+d(z,y)<r+ε<r+(d(x,y)−r)=d(x,y).\begin{aligned} d(x,y) &\le d(x,z) + d(z,y) \\ &< r + \varepsilon \\ &< r + \big(d(x,y) - r\big) \\ &= d(x,y). \end{aligned}

This gives d(x,y)<d(x,y)d(x,y) < d(x,y), a contradiction. Hence no such zz exists, so B(y,ε)⊆UB(y,\varepsilon)\subseteq U. Taking the union over all y∈Uy\in U shows UU is open, and therefore B‾(x,r)\overline{B}(x,r) is closed. ■\blacksquare

Summary