The Timpson Lyceum seal

The Timpson Lyceum · General Topology (Point Set Topology)

Open Sets – Lecture 6 (Topology)

Open Sets – Lecture 6

Overview

This lecture cements the definition of a topology and the language of open sets, then puts that definition to work. We review the three axioms a collection of subsets must satisfy to be a topology, revisit the trivial and discrete topologies, and build the central running example of the course: the finite complement topology on R\mathbb{R}. We then prove that this construction really is a topology, introduce the notions of finer and coarser topologies, define a topological space and a neighborhood, and prove an "open iff locally open" characterization. Two homework results close the lecture: the discrete and finite complement topologies coincide on a finite set but differ on an infinite one, and a quick characterization of the discrete topology in terms of singletons.

Key Concepts

Topology. Let XX be a set and let τ\tau be a collection of subsets of XX. Then τ\tau is a topology on XX if it satisfies three properties:

Open set. A set is open exactly when it is a member of the topology τ\tau. "Open" is just shorthand for "in τ\tau," used so we don't keep saying "in the topology."

Power set. P(X)\mathcal{P}(X) is the set of all subsets of XX. For example, P({a,b})={ ∅, {a}, {b}, {a,b} }.\mathcal{P}(\{a,b\}) = \{\,\varnothing,\ \{a\},\ \{b\},\ \{a,b\}\,\}. Every topology on XX is a subset of P(X)\mathcal{P}(X), since a topology is built from subsets of XX.

Trivial topology. τ={∅,X}\tau = \{\varnothing, X\}. The smallest possible topology on any set.

Discrete topology. τ=P(X)\tau = \mathcal{P}(X), every subset is open. The largest possible topology. It satisfies all three axioms because any intersection or union of subsets of XX is again a subset of XX.

Finite complement topology RFC\mathbb{R}_{FC} (the lecture's central example). On R\mathbb{R}, declare a set open when its complement is finite, or when the set is empty: τ={ U⊆R:R∖U is finite }∪{∅}.\tau = \{\, U \subseteq \mathbb{R} : \mathbb{R} \setminus U \text{ is finite} \,\} \cup \{\varnothing\}.

Topological space. The ordered pair (X,τ)(X, \tau) — a set together with a topology on it. (Compare a sample space in probability: a set bundled with structure.)

Finer and coarser. Given two topologies τ1\tau_1 and τ2\tau_2 on the same set XX:

Neighborhood. Given (X,τ)(X, \tau) and a point x∈Xx \in X, any open set Ux∈τU_x \in \tau with x∈Uxx \in U_x is a neighborhood of xx. The notation UxU_x always means an open set containing the point xx.

"Open iff locally open" theorem. Let (X,τ)(X, \tau) be a topological space and A⊆XA \subseteq X. Then AA is open if and only if for every x∈Ax \in A there exists an open set Ux∈τU_x \in \tau with x∈Ux⊆Ax \in U_x \subseteq A. (Forward direction is immediate: take Ux=AU_x = A. Reverse direction unions all the UxU_x to recover AA, via the union lemma.)

Singleton characterization of the discrete topology. τ=P(X)\tau = \mathcal{P}(X) if and only if {x}∈τ\{x\} \in \tau for every x∈Xx \in X. Once every singleton is open, any subset is a union of singletons and therefore open.

Discrete vs. finite complement. On a finite set, P(X)=RFC\mathcal{P}(X) = \mathbb{R}_{FC}-style finite complement topology — they are the same. On an infinite set they differ: a singleton {a}\{a\} is open in the discrete topology but not in the finite complement topology, since its complement X∖{a}X \setminus \{a\} is infinite.

Worked Example

Claim: The finite complement topology RFC\mathbb{R}_{FC} is a topology — verify the finite-intersection axiom for nonempty open sets.

Let U1,…,Un∈RFCU_1, \dots, U_n \in \mathbb{R}_{FC} with no Ui=∅U_i = \varnothing. Each is open, so each has a finite complement: there is a finite set FiF_i with Ui=R∖FiU_i = \mathbb{R} \setminus F_i. The key set identity (a generalized De Morgan law, proved by writing membership as a logical conjunction and factoring out the negation) is:

⋂i=1nUi=⋂i=1n(R∖Fi)=R∖⋃i=1nFi.\begin{aligned} \bigcap_{i=1}^{n} U_i &= \bigcap_{i=1}^{n} \left( \mathbb{R} \setminus F_i \right) \\ &= \mathbb{R} \setminus \bigcup_{i=1}^{n} F_i. \end{aligned}

A finite union of finite sets ⋃i=1nFi\bigcup_{i=1}^{n} F_i is finite, so R∖⋃Fi\mathbb{R} \setminus \bigcup F_i has a finite complement and is therefore open — i.e. ⋂Ui∈RFC\bigcap U_i \in \mathbb{R}_{FC}. (If some Ui=∅U_i = \varnothing, the whole intersection is ∅\varnothing, which is in τ\tau by definition. The ∅,X\varnothing, X and arbitrary-union axioms are checked similarly, the union argument relying on the fact that unioning sets only shrinks the complement.) ■\blacksquare

Summary