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The Timpson Lyceum · Calculus 1 (2024)

Geometry, Trig, Sets, Relations, & Functions Review - Lecture 1 (Calculus 1)

Overview

This opening lecture is a supplementary review that lays the geometric, trigonometric, and set-theoretic foundations needed for calculus before the textbook is opened. It builds trigonometry from four core ideas — the radian, π\pi, sine, and cosine — and shows how the unit circle encodes the coordinates of special angles. It then rebuilds the language of mathematics from the ground up: sets, relations, and functions, all defined precisely as collections of objects and ordered pairs. The goal is fluency: being able to fill in a unit circle quickly from memory and to reason about functions as sets of ordered pairs that get plotted as graphs.

Key Concepts

Angle sum of a triangle

Pythagorean theorem

The four foundations of trig

Degree–radian conversion

Scaling beyond the unit circle

The six trig functions (all derived from sine and cosine)

Special-angle values (memorize the unit circle)

Sets

Set relations (evaluate to true/false)

Set operations (take sets, return sets)

Lists, relations, and functions

Graphs, domain, range, intervals

Worked Example

Solve the triangle with hypotenuse r=8r = 8 and base angle θ=π6\theta = \tfrac{\pi}{6}, finding the horizontal leg xx and vertical leg yy. Use the scaled unit-circle relations x=rcos⁡θx = r\cos\theta and y=rsin⁡θy = r\sin\theta, with cos⁡π6=32\cos\tfrac{\pi}{6}=\tfrac{\sqrt{3}}{2} and sin⁡π6=12\sin\tfrac{\pi}{6}=\tfrac{1}{2}.

x=rcos⁡θ=8cos⁡π6=8⋅32=43y=rsin⁡θ=8sin⁡π6=8⋅12=4\begin{aligned} x &= r\cos\theta = 8\cos\tfrac{\pi}{6} = 8\cdot\tfrac{\sqrt{3}}{2} = 4\sqrt{3} \\ y &= r\sin\theta = 8\sin\tfrac{\pi}{6} = 8\cdot\tfrac{1}{2} = 4 \end{aligned}

So the triangle has horizontal leg 434\sqrt{3} and height 44.

Summary