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The Timpson Lyceum · University Physics I (2025)

Newton's Laws of Motion – Lecture 4 (University Physics I)

Overview

This lecture moves us out of kinematics — describing motion — and into dynamics, the study of the forces that cause motion. It lays out Newtonian mechanics as an axiomatic system: a handful of undefined primitives (space, time, particle, mass, force) plus Newton's laws as the postulates we validate by observation. From these we get the modern, careful statements of Newton's three laws of motion, the idea of an inertial reference frame, the fundamental sources of force in nature, and the everyday force types you will meet in problems. The math is light here, but conceptually this is one of the most important lectures in the course because every later topic rests on ∑F⃗=ma⃗\sum \vec F = m\vec a.

Key Concepts

Primitives (undefined terms). Newtonian mechanics presupposes, without defining, five things: space, time, particle, mass, and force. Space is modeled by ordinary 3-D Euclidean space R3\mathbb{R}^3 (Pythagorean theorem holds, no curvature); time is modeled by the real numbers. A particle is a point-like model of a real object, carrying a position r⃗\vec r at a time tt; its trajectory is r⃗(t)\vec r(t). We model real objects (a book, a car) as particles. Because R3\mathbb{R}^3 comes pre-packaged, we inherit vectors, Euclidean geometry, and calculus for free.

Newton's "zeroth law" — forces are vectors. A real force is modeled by a vector. The consequence is superposition: the net (resultant) force on an object is the vector sum of the individual forces, F⃗net=∑iF⃗i\vec F_{\text{net}}=\sum_i \vec F_i. This is an observed fact about our universe, not a logical necessity.

Newton's first law (law of inertia). There exists a reference frame in which an object with zero net force has constant velocity (zero acceleration): at rest it stays at rest, in motion it stays in motion. The crucial, often-omitted clause is the existence of such a frame.

Newton's second law. In an inertial frame, the sum of the external forces on an object equals its mass times its acceleration: ∑F⃗ext=ma⃗.\sum \vec F_{\text{ext}} = m\vec a. Because forces are vectors, this splits into independent component equations: ∑Fx=max,∑Fy=may,∑Fz=maz.\sum F_x = ma_x,\quad \sum F_y = ma_y,\quad \sum F_z = ma_z. Only forces acting on the object count — never the forces the object exerts on something else, and never "internal" forces (you cannot accelerate yourself by pushing on yourself; running works via the external friction force from the ground).

Newton's third law. In an inertial frame, the force object AA exerts on object BB is equal and opposite to the force BB exerts on AA: F⃗A on B=− F⃗B on A\vec F_{A\text{ on }B} = -\,\vec F_{B\text{ on }A}. These action–reaction pairs act on different objects, so they never both appear in a single object's second-law sum. (Lean on a wall: you push it, it pushes back equally — no motion.)

Sources of force. All forces ultimately reduce to four fundamental interactions: gravity, the electromagnetic force (responsible for nearly every contact-type force in this course — why your hand doesn't pass through a wall), the weak nuclear force (radioactive decay), and the strong nuclear force (binds the nucleus). In practice we use only gravity and electromagnetism.

Everyday force types.

Units. Force is measured in newtons: 1 N=1 kg⋅m/s21\ \text{N} = 1\ \text{kg}\cdot\text{m/s}^2, the force that gives a 1 kg1\ \text{kg} mass an acceleration of 1 m/s21\ \text{m/s}^2.

Mass vs. weight. Mass measures an object's resistance to acceleration (inertia) and the amount of matter; it is intrinsic. Weight is the gravitational force on it, w=mgw=mg, and vanishes far from any mass. Remarkably, inertial mass and gravitational mass are experimentally identical to about 1 part in 101210^{12}. Mass can be measured without gravity: pull an ideal spring the same distance with the unknown mass and with a 1 kg1\ \text{kg} standard; equal forces give m a1=(1) a2m\,a_1 = (1)\,a_2, so m=a2/a1m = a_2/a_1.

Worked Example

Two wrestlers tug a championship belt. Three forces act on the belt: F1=250 NF_1 = 250\ \text{N} at 53∘53^\circ above the −x-x axis, F2=50 NF_2 = 50\ \text{N} along +x+x, and F3=120 NF_3 = 120\ \text{N} straight down. Find the net force's components, magnitude, and direction. Take right as +x+x and up as +y+y.

Resolve F⃗1\vec F_1 into components and sum each axis:

∑Fx=F2−F1cos⁡53∘=50−250cos⁡53∘≈−100 N∑Fy=F1sin⁡53∘−F3=250sin⁡53∘−120≈80 N\begin{aligned} \sum F_x &= F_2 - F_1\cos 53^\circ = 50 - 250\cos 53^\circ \approx -100\ \text{N} \\ \sum F_y &= F_1\sin 53^\circ - F_3 = 250\sin 53^\circ - 120 \approx 80\ \text{N} \end{aligned}

Magnitude and direction:

Fnet=(∑Fx)2+(∑Fy)2=(−100)2+802≈130 Nθ=tan⁡−1 ⁣(∣∑Fy∣∣∑Fx∣)=tan⁡−1 ⁣(80100)≈39∘\begin{aligned} F_{\text{net}} &= \sqrt{(\textstyle\sum F_x)^2 + (\sum F_y)^2} = \sqrt{(-100)^2 + 80^2} \approx 130\ \text{N} \\ \theta &= \tan^{-1}\!\left(\frac{|\sum F_y|}{|\sum F_x|}\right) = \tan^{-1}\!\left(\frac{80}{100}\right) \approx 39^\circ \end{aligned}

Since ∑Fx<0\sum F_x<0 and ∑Fy>0\sum F_y>0, the resultant lies in the second quadrant: 39∘39^\circ above the −x-x direction, or equivalently 180∘−39∘=141∘180^\circ-39^\circ = 141^\circ measured from +x+x.

Short example — friction on a sliding bottle. A 0.45 kg0.45\ \text{kg} ketchup bottle leaves a hand at v0=2.8 m/sv_0 = 2.8\ \text{m/s} and slides 1.0 m1.0\ \text{m} to rest. Find the friction force. First get the acceleration from kinematics, then apply the second law:

v2=v02+2a Δx  ⇒  a=0−(2.8)22(1.0)=−3.92 m/s2f=ma=(0.45)(−3.92)≈−1.8 N\begin{aligned} v^2 &= v_0^2 + 2a\,\Delta x \;\Rightarrow\; a = \frac{0 - (2.8)^2}{2(1.0)} = -3.92\ \text{m/s}^2 \\ f &= ma = (0.45)(-3.92) \approx -1.8\ \text{N} \end{aligned}

So friction is 1.8 N1.8\ \text{N} directed opposite the motion.

Summary